- Homer’s mother has four children. Three of the children are named Spring, Summer, and Autumn. What is the name of the 4th child?
- A man tossed a baseball 20 feet. It stopped in mid-air, reversed directions and came back to him. How can this be explained?
- [An old classic!] A brick weighs 3 pounds plus half (the weight of) a brick. How much does a brick and a half weigh?
- Find three consecutive odd integers which are all prime.
- You have a string of 10 consecutive integers. The sum of the first three is 39. What is the sum of the last 3?
- If x#y = x + y +7, then what is the value of (2#3) # (7#0)?
- I have twice as many nickels as dimes. If the value of my nickels is $5.00, what is the value of my dimes?
- My neighbor has four daughters and each daughter has exactly one brother. How many children does my neighbor have?
- What is the largest integer you can square and get an answer less than 3000?
- 1/19 is to 1/17 as what number is to 95?
- In the first quarter of a game, the Denver Nuggets missed only 7 of their 25 field goal attempts. What was their scoring percentage for that quarter?
- Simplify this expression: (99 – 9) x (99 – 19) x (99 – 29) x . . . x (99 – 199).
- In my hand, I have two US coins whose total value is 55 cents, but one of the coins is not a nickel. What are the two coins?
- A frog is at the bottom of a 30-foot well. Each day he is able to jump up 5 ft, but during the nigth, he slides down 3 ft. How many days will it take him to jump out of the well?
- “Brothers and sisters have I none, but this man’s father is my father’s son.” To whom is the speaker referring?
BONUSES
B1. Counterfeit Coin #4 Another new twist of Jan/Feb’s problems. I am now convinced this problem can be solved with up to 27 coins(!). So pick your own number(s) and solve: You know one of them is counterfeit – and that it is slightly heavier than the good coins, and you still have your balance scale. Determine the bad coin, still with only 3 weighings. (A ‘weighing’ consists of coins being placed on both sides.)
B2. (see #4 above.) It turns out there is only one solution to #4 above. Why is that?
B3. (see #6 above.) If x&y = x # (y+7), then what is the value of (2#3) & (7#0)?
B4. (see #9 above.) Suppose we do not insist on an integer in #9 above. How (if any) does that change the answer?
1. Homer.
2. The ball is thrown up.
3. 1 brick is 6 pounds, 1 1/2 bricks are 9 pounds
3+1/2x = x
3 = 1/2 ×
6 = x
4. 3, 5, 7
5. 48 = 15+16+17
27 = 8+9+10
6. Larry, I am an old fart and have no idea what is even being asked let alone know how to solve this one.
B2. 1,3,5 are not 3 consecutive prime numbers because mathematicians have a thing about the number 1.
Mathematicians make up excuses why 1 is excluded from the prime numbers, like 1 does not meet the definition of s prime. A prime number, according to mathematicians is an integer greater than one whose factors are itself and 1. So, mathematicians simply exclude 1 by definition. Is this fair? Mathematicians try to justify the definitiom excluding 1 by introducing the property of irreducibility and labeling 1 a unit rather than a prime. Poor number 1 being left out in the cold and bearing the weight of unity. I am reminded of the Three Dog Night song, One is the Lonliest Number.
Historically 1 was a prime and it has been a rather recent campaign started by Euclud to exclude 1 from the prime numbers.
There will be a march in Washington, D.C. in January with the hope President Trump will sign an axecutive order returning 1 to the ranks of primes.
1. Homer
2. He threw it straight UP
4. 3, 5, 7
5. sum of last 3 = 60
6. 33
1. WINTER
2. HE TOSSED IT STRAIGHT UP
3. 6.75
8.5
1.Homer
2.he threw it up in air
3. 9 lb
4. 3,5,7
5. 60
6.zero
7. $5.00
8. 5 children
9.54
10.
13. 2 quarters and a nickel ( one IS a nickel but one , at least, is not a nickel.
14. 14 days ( before the night comes and he slides back 3)
15.. His son
1. Homer
2. He threw the ball straight up in the air.
7. 5.00
8. 5 children
13. A half dollar and a nickel. The other coin is a nickel.
14. 14 Days
15. Himself
#10. 85
I didn’t try #10 before.
7. $5 in dimes
8. 5 children
9. 54
10. 85
B4. You could simply take the square root of 3000 and then give the decimal value ONE LESS than the specified decimal place (or choose a place to go to).
11. 72%
12. Zero